Linear Algebra and Its Applications, Review Exercise 1.2

Posted on July 14, 2011 by hecker

Review exercise 1.2. Given matrices A and B as follows

A = \begin{bmatrix} 1&0 \\ 2&1 \end{bmatrix} \qquad B = \begin{bmatrix} 1&2 \\ 0&1 \end{bmatrix}

find the products AB and BA, the inverses A^{-1}, B^{-1}, and (AB)^{-1}.

Answer: We have

AB = \begin{bmatrix} 1&0 \\ 2&1 \end{bmatrix} \begin{bmatrix} 1&2 \\ 0&1 \end{bmatrix} = \begin{bmatrix}1&2 \\ 2&5 \end{bmatrix}

BA = \begin{bmatrix} 1&2 \\ 0&1 \end{bmatrix} \begin{bmatrix} 1&0 \\ 2&1 \end{bmatrix} = \begin{bmatrix}5&2 \\ 2&1 \end{bmatrix}

A^{-1} = \frac{1}{1 \cdot 1 - 2 \cdot 0} \begin{bmatrix} 1&-0 \\ -2&1 \end{bmatrix} = \begin{bmatrix} 1&0 \\ -2&1 \end{bmatrix}

B^{-1} = \frac{1}{1 \cdot 1 - 2 \cdot 0} \begin{bmatrix} 1&-2 \\ -0&1 \end{bmatrix} = \begin{bmatrix} 1&-2 \\ 0&1 \end{bmatrix}

(AB)^{-1} = B^{-1}A^{-1} = \begin{bmatrix} 1&-2 \\ 0&1 \end{bmatrix} \begin{bmatrix} 1&0 \\ -2&1 \end{bmatrix} = \begin{bmatrix} 5&-2 \\ -2&1 \end{bmatrix}

NOTE: This continues a series of posts containing worked out exercises from the (out of print) book Linear Algebra and Its Applications, Third Edition by Gilbert Strang.

If you find these posts useful I encourage you to also check out the more current Linear Algebra and Its Applications, Fourth Edition, Dr Strang’s introductory textbook Introduction to Linear Algebra, Fourth Edition and the accompanying free online course, and Dr Strang’s other books.

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