Exercise 3.1.21. If is the plane in
described by
what is the equation for the plane
parallel to
through the origin? What is a vector perpendicular to
? Find a matrix
for which
is the nullspace, and a matrix
for which
is the row space.
Answer: One way to approach this problem is to find a general solution to the equation and express it as the sum of a homogeneous solution and a particular solution. The corresponding homogeneous system is
, which is represented by the matrix
This system has as a basic variable and
and
as free variables. Setting
and
we have
or
. So
is one solution to the homogeneous system. Setting
and
we have
or
. So
is a second solution to the homogeneous system. These vectors are in the nullspace of
and serve as a basis for it.
To find the particular solution we set for the general system so that we have
or
. So
is a particular solution to the general system, and the general solution to the equation is then the sum of the particular solution and the homogeneous solution:
The plane is defined by the general solution to
. The plane
going through the origin corresponds to the homogeneous system
and is spanned by the vectors
and
; it is the nullspace of the matrix
above. The plane
is parallel to
and is offset from it by the vector
.
To find a vector perpendicular to (and
), from the above solution to the homogeneous system
we know that the vector
(the first and only row of the matrix
above) is orthogonal to the vectors
and
(the basis vectors for the nullspace of
). Therefore the vector
is perpendicular to the plane
, the nullspace of
spanned by
and
.
Using the vectors and
that serve as a basis for the plane
we can construct a matrix
for which
is the row space:
NOTE: This continues a series of posts containing worked out exercises from the (out of print) book Linear Algebra and Its Applications, Third Edition by Gilbert Strang.
If you find these posts useful I encourage you to also check out the more current Linear Algebra and Its Applications, Fourth Edition, Dr Strang’s introductory textbook Introduction to Linear Algebra, Fourth Edition
and the accompanying free online course, and Dr Strang’s other books
.