Exercise 3.3.8. Suppose that is a projection matrix from onto a subspace with dimension . What is the column space of ? What is its rank?

Answer: Suppose that is a arbitrary vector in . From the definition of we know that is a vector in . But is a linear combination of the columns of , so that also is in the column space . Since any vector in can be expressed as for some , all vectors in are also in , so that .

Now suppose that is an arbitrary vector in the column space . Then can be expressed as a linear combination of the columns of for some set of coefficients . Consider the vector . We then have by the definition of . But if for some then is in . So all vectors in are also in and thus .

Since and we then have : The column space of is .

The rank of is the dimension of its column space. But since is the column space of , the rank of is , the dimension of .

NOTE: This continues a series of posts containing worked out exercises from the (out of print) book Linear Algebra and Its Applications, Third Edition by Gilbert Strang.

If you find these posts useful I encourage you to also check out the more current Linear Algebra and Its Applications, Fourth Edition, Dr Strang’s introductory textbook Introduction to Linear Algebra, Fourth Edition and the accompanying free online course, and Dr Strang’s other books.

### Like this:

Like Loading...

*Related*